Optimal. Leaf size=226 \[ \frac {2 \sin ^{\frac {5}{2}}(a+b x)}{5 b \cos ^{\frac {5}{2}}(a+b x)}-\frac {2 \sqrt {\sin (a+b x)}}{b \sqrt {\cos (a+b x)}}+\frac {\tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{\sqrt {2} b}-\frac {\tan ^{-1}\left (\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1\right )}{\sqrt {2} b}-\frac {\log \left (\cot (a+b x)-\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1\right )}{2 \sqrt {2} b}+\frac {\log \left (\cot (a+b x)+\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1\right )}{2 \sqrt {2} b} \]
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Rubi [A] time = 0.15, antiderivative size = 226, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 8, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.381, Rules used = {2566, 2575, 297, 1162, 617, 204, 1165, 628} \[ \frac {2 \sin ^{\frac {5}{2}}(a+b x)}{5 b \cos ^{\frac {5}{2}}(a+b x)}-\frac {2 \sqrt {\sin (a+b x)}}{b \sqrt {\cos (a+b x)}}+\frac {\tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{\sqrt {2} b}-\frac {\tan ^{-1}\left (\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1\right )}{\sqrt {2} b}-\frac {\log \left (\cot (a+b x)-\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1\right )}{2 \sqrt {2} b}+\frac {\log \left (\cot (a+b x)+\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}+1\right )}{2 \sqrt {2} b} \]
Antiderivative was successfully verified.
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Rule 204
Rule 297
Rule 617
Rule 628
Rule 1162
Rule 1165
Rule 2566
Rule 2575
Rubi steps
\begin {align*} \int \frac {\sin ^{\frac {7}{2}}(a+b x)}{\cos ^{\frac {7}{2}}(a+b x)} \, dx &=\frac {2 \sin ^{\frac {5}{2}}(a+b x)}{5 b \cos ^{\frac {5}{2}}(a+b x)}-\int \frac {\sin ^{\frac {3}{2}}(a+b x)}{\cos ^{\frac {3}{2}}(a+b x)} \, dx\\ &=-\frac {2 \sqrt {\sin (a+b x)}}{b \sqrt {\cos (a+b x)}}+\frac {2 \sin ^{\frac {5}{2}}(a+b x)}{5 b \cos ^{\frac {5}{2}}(a+b x)}+\int \frac {\sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}} \, dx\\ &=-\frac {2 \sqrt {\sin (a+b x)}}{b \sqrt {\cos (a+b x)}}+\frac {2 \sin ^{\frac {5}{2}}(a+b x)}{5 b \cos ^{\frac {5}{2}}(a+b x)}-\frac {2 \operatorname {Subst}\left (\int \frac {x^2}{1+x^4} \, dx,x,\frac {\sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{b}\\ &=-\frac {2 \sqrt {\sin (a+b x)}}{b \sqrt {\cos (a+b x)}}+\frac {2 \sin ^{\frac {5}{2}}(a+b x)}{5 b \cos ^{\frac {5}{2}}(a+b x)}+\frac {\operatorname {Subst}\left (\int \frac {1-x^2}{1+x^4} \, dx,x,\frac {\sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{b}-\frac {\operatorname {Subst}\left (\int \frac {1+x^2}{1+x^4} \, dx,x,\frac {\sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{b}\\ &=-\frac {2 \sqrt {\sin (a+b x)}}{b \sqrt {\cos (a+b x)}}+\frac {2 \sin ^{\frac {5}{2}}(a+b x)}{5 b \cos ^{\frac {5}{2}}(a+b x)}-\frac {\operatorname {Subst}\left (\int \frac {1}{1-\sqrt {2} x+x^2} \, dx,x,\frac {\sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{2 b}-\frac {\operatorname {Subst}\left (\int \frac {1}{1+\sqrt {2} x+x^2} \, dx,x,\frac {\sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{2 b}-\frac {\operatorname {Subst}\left (\int \frac {\sqrt {2}+2 x}{-1-\sqrt {2} x-x^2} \, dx,x,\frac {\sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{2 \sqrt {2} b}-\frac {\operatorname {Subst}\left (\int \frac {\sqrt {2}-2 x}{-1+\sqrt {2} x-x^2} \, dx,x,\frac {\sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{2 \sqrt {2} b}\\ &=-\frac {\log \left (1+\cot (a+b x)-\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{2 \sqrt {2} b}+\frac {\log \left (1+\cot (a+b x)+\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{2 \sqrt {2} b}-\frac {2 \sqrt {\sin (a+b x)}}{b \sqrt {\cos (a+b x)}}+\frac {2 \sin ^{\frac {5}{2}}(a+b x)}{5 b \cos ^{\frac {5}{2}}(a+b x)}-\frac {\operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{\sqrt {2} b}+\frac {\operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{\sqrt {2} b}\\ &=\frac {\tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{\sqrt {2} b}-\frac {\tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{\sqrt {2} b}-\frac {\log \left (1+\cot (a+b x)-\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{2 \sqrt {2} b}+\frac {\log \left (1+\cot (a+b x)+\frac {\sqrt {2} \sqrt {\cos (a+b x)}}{\sqrt {\sin (a+b x)}}\right )}{2 \sqrt {2} b}-\frac {2 \sqrt {\sin (a+b x)}}{b \sqrt {\cos (a+b x)}}+\frac {2 \sin ^{\frac {5}{2}}(a+b x)}{5 b \cos ^{\frac {5}{2}}(a+b x)}\\ \end {align*}
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Mathematica [C] time = 0.05, size = 57, normalized size = 0.25 \[ \frac {2 \sin ^{\frac {9}{2}}(a+b x) \sqrt [4]{\cos ^2(a+b x)} \, _2F_1\left (\frac {9}{4},\frac {9}{4};\frac {13}{4};\sin ^2(a+b x)\right )}{9 b \sqrt {\cos (a+b x)}} \]
Antiderivative was successfully verified.
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fricas [B] time = 26.09, size = 1282, normalized size = 5.67 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 0.16, size = 692, normalized size = 3.06 \[ -\frac {\left (5 i \left (\cos ^{2}\left (b x +a \right )\right ) \sin \left (b x +a \right ) \sqrt {\frac {1-\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \sqrt {\frac {-1+\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \sqrt {\frac {-1+\cos \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \EllipticPi \left (\sqrt {\frac {1-\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}, \frac {1}{2}-\frac {i}{2}, \frac {\sqrt {2}}{2}\right )-5 i \left (\cos ^{2}\left (b x +a \right )\right ) \sin \left (b x +a \right ) \sqrt {\frac {1-\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \sqrt {\frac {-1+\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \sqrt {\frac {-1+\cos \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \EllipticPi \left (\sqrt {\frac {1-\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}, \frac {1}{2}+\frac {i}{2}, \frac {\sqrt {2}}{2}\right )+5 \left (\cos ^{2}\left (b x +a \right )\right ) \sin \left (b x +a \right ) \sqrt {\frac {1-\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \sqrt {\frac {-1+\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \sqrt {\frac {-1+\cos \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \EllipticPi \left (\sqrt {\frac {1-\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}, \frac {1}{2}-\frac {i}{2}, \frac {\sqrt {2}}{2}\right )+5 \left (\cos ^{2}\left (b x +a \right )\right ) \sin \left (b x +a \right ) \sqrt {\frac {1-\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \sqrt {\frac {-1+\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \sqrt {\frac {-1+\cos \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \EllipticPi \left (\sqrt {\frac {1-\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}, \frac {1}{2}+\frac {i}{2}, \frac {\sqrt {2}}{2}\right )-10 \left (\cos ^{2}\left (b x +a \right )\right ) \sin \left (b x +a \right ) \sqrt {\frac {1-\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \sqrt {\frac {-1+\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \sqrt {\frac {-1+\cos \left (b x +a \right )}{\sin \left (b x +a \right )}}\, \EllipticF \left (\sqrt {\frac {1-\cos \left (b x +a \right )+\sin \left (b x +a \right )}{\sin \left (b x +a \right )}}, \frac {\sqrt {2}}{2}\right )+12 \left (\cos ^{3}\left (b x +a \right )\right ) \sqrt {2}-12 \left (\cos ^{2}\left (b x +a \right )\right ) \sqrt {2}-2 \cos \left (b x +a \right ) \sqrt {2}+2 \sqrt {2}\right ) \left (\sqrt {\sin }\left (b x +a \right )\right ) \sqrt {2}}{10 b \left (-1+\cos \left (b x +a \right )\right ) \cos \left (b x +a \right )^{\frac {5}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sin \left (b x + a\right )^{\frac {7}{2}}}{\cos \left (b x + a\right )^{\frac {7}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 2.05, size = 44, normalized size = 0.19 \[ \frac {2\,{\sin \left (a+b\,x\right )}^{9/2}\,{{}}_2{\mathrm {F}}_1\left (-\frac {5}{4},-\frac {5}{4};\ -\frac {1}{4};\ {\cos \left (a+b\,x\right )}^2\right )}{5\,b\,{\cos \left (a+b\,x\right )}^{5/2}\,{\left ({\sin \left (a+b\,x\right )}^2\right )}^{9/4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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